How to schedule an Oozie job to run at 8PM EDT?

[#1 · Accepted solution]

Look at the Oozie coordinator documentation, the timezone value will be "America/New_York" and start would be something like "2015-10-12T08:00Z". Alternatively you can do a cron like thing, see the example in the following blog. Based on that it can be something like:

<coordinator-app name="weekdays-at-eight-pm"
  frequency="0 20 * * 2-6"
  start="${start}" end="${end}" timezone="America/New_York"
  xmlns="uri:oozie:coordinator:0.2">
...
</coordinator-app>

[#2]

Will this be a problem when DayLightSaving change takes place from EDT TO EST.

Also I tried your solution, and the coordinator actions are being generated at 8 PM UTC timezone not 8 PM EDT.

From what I read in other blogs, Do I need to change my oozie.processing.timezone to EDT to make the above thing work?

[#3]

This is not working gives paramter frequency must be an integer Parsing error for input string "0 20 * * 2-6"

[#4]

I had the same issue, because I put the frequency in the dataset as a cron, we can't actually do that.

Here is my example :

<coordinator-app name="weekdays-at-two-am"
frequency="0 2 * * 2-6"
start="${start} "
end="${end}"
timezone="Europe/Paris"
xmlns="uri:oozie:coordinator:0.4">
<datasets>
	<dataset name="my_dataset_name"
	 	frequency="${coord:days(1)}"
	 	initial-instance="2017-12-28T02:00+0100"
	 	timezone="Europe/Paris">
		<uri-template>${my_path}/${YEAR}${MONTH}${DAY}</uri-template>
		<done-flag>my_flag</done-flag>
	</dataset>
</datasets>
<input-events>
    <data-in name="log_input_name" dataset="my_dataset_name">
        <instance>${coord:current(0)}</instance>
    </data-in>
</input-events>

my coordinator is lunched with the cron at first (line 2), but it verifies the second condition which looking every day (line9) for the flag of the current day (line 18)