There are several Scala native JSON libraries available (json4s, play-json, circe, as well as others) so there are lots of ways to do this.
With play-json, your solution might look like:
import play.api.libs.json._
import play.api.libs.json.Reads._
import play.api.libs.functional.syntax._
val jsonStr = """{"Id":1,"Name":"Babu","Address":"dsfjskkjfs"}"""
Person(id: Int, name: String, address: String)
implicit val personReads: Reads[Person] = (
(JsPath \ "Id").read[Int] and
(JsPath \ "Name").read[String] and
(JsPath \ "Address").read[String]
)(Person.apply _)
jsonStr.validate[Person] match {
case JsSuccess(person, _) => {
// do something
}
case JsError(e) => {
// do something
}
}
With circe, your solution might look like:
import io.circe._
import io.circe.generic.auto._
import io.circe.parser._
import io.circe.syntax._
val jsonStr = """{"Id":1,"Name":"Babu","Address":"dsfjskkjfs"}"""
Person(id: Int, name: String, address: String)
decode[Person](jsonStr) match {
case Right(person) => {
// do something with Person(1, "Babu", "dsfjskkjfs")
}
case Left(e) => {
// handle error
}
}
In your question you asked for a case class but wrote it out as a tuple, so just to close that loop, if you want to subsequently convert the data to a tuple you can do `Person.unapply(person).get`.
