About Tomas79

Tomas79 · ‎12-06-2017

Have you installed Unlimited cryptography for JAVA? (JCE) Maybe there is a problem, that the algortihm is too strong.

Tomas79 · ‎12-06-2017

Try the solution from this post http://community.cloudera.com/t5/Advanced-Analytics-Apache-Spark/ClassNotFoundException-org-apache-htrace-Trace-exception-in/td-p/29200

Tomas79 · ‎12-01-2017

For Mapreduce and Spark jobs (running on YARN) you should be able to report from Resource Pools. There is a chart of Per Pool allocation, containers running etc. Of course Impala usage is not included, there you have to report from Impala Queries Workload summary and manually report from the history of queries - you have to choose a KPI, whether it is cpu time, or HDFS scanned or something else.

Tomas79 · ‎11-30-2017

Have you resolved this? I had a similar issue, but did not find any answer for that

Tomas79 · ‎11-26-2017

You can check it by SHOW CURRENT ROLES what priviliges you have under this user

Tomas79 · ‎11-26-2017

If the user really has a server ALL, then he can do anything. So I beleive, that the users group is not resolved correclty to a "regular_group" and therefore the Query does not pass throught the security check.

Tomas79 · ‎11-26-2017

Try to change your producer config: com.sun.security.auth.module.Krb5LoginModule required useTicketCache=false useKeyTab=true storeKey=true keyTab="path to the file.keytab" principal="kafka/ip-10-197-17-69.eu-west-1.compute.internal@DOMAIN" And try to change the consumer config: security.protocol=SASL_PLAINTEXT sasl.mechanism=GSSAPI sasl.kerberos.service.name=kafka

Tomas79 · ‎11-26-2017

Do you have this directory created? Are the permissions correctly set on this path?

Tomas79 · ‎11-26-2017

Try to use a newer version of Java 1.8, Do you have other Java installed as well (openjdk)?

Tomas79 · ‎11-26-2017

Of course you have a error. Because the insert statement tries to do this: INSERT INTO TABLE am_temp2 Partition (search_date=2017-11-18) insted of this: INSERT INTO TABLE am_temp2 Partition (search_date="2017-11-18") or this: INSERT INTO TABLE am_temp2 Partition (search_date=20171118)

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