Tou can convert a org.apache.mahout.math.Vector into a org.apache.spark.mllib.linalg.Vector by using the iterateNonZero() or iterateAll() methods of org.apache.mahout.math.Vector. In fact, if you Vector is sparse the first option is the best. In this case you can build two arrays via the iterateNonZero: one containing all the non-zero indexes and the other with the corresponding values, i.e. ArrayList<Double> values = new ArrayList<Double>();
ArrayList<Integer> indexes = new ArrayList<Integer>();
org.apache.mahout.math.Vector v = ...
Iterator<Element> it = v.iterateNonZero();
while(it.hasNext()){
Element e = it.next();
values.add(e.get());
indexes.add(e.index());
}
Vectors.sparse(v.size(), indexes.toArray(new Integer[indexes.size()]) ,values.toArray(new Double[values.size()])); You can do the same thing if you have a dense Vector using the iterateAll() method and Vectors.dense.
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