When I run the following: <code>val df1 = sqlContext.read.format("orc").load(myPath) df1.columns.map(m => println(m)) The columns are printed as '_col0', '_col1', '_col2' etc. As opposed to their real names such as 'empno', 'name', 'deptno'. When I 'describe mytable' in Hive it prints the column name correctly, but when I run 'orcfiledump' it shows _col0, _col1, _col2 as well. Do I have to specify 'schema on read' or something? If yes, how do I do that in Spark/Scala? <code>hive --orcfiledump /apps/hive/warehouse/mydb.db/mytable1 ..... fieldNames:"_col0" fieldNames:"_col1" fieldNames:"_col2" As suggested elsewhere I've added '--files' BEFORE '--jars' as follows: spark-submit \ --master yarn \ --deploy-mode cluster \ --class xxx.xxxx.MyDriver \ --files hive-site.xml \ --jars datanucleus-api-jdo-3.2.6.jar,datanucleus-core-3.2.10.jar,datanucleus-rdbms-3.2.9.jar \ --name MyDriver \ --num-executors 1 \ --driver-memory 1g \ --executor-memory 1g \ --executor-cores 1 \ ./my-utils-1.0-SNAPSHOT.jar Note: I created the table as follows: <code>create table mydb.mytable1 (empno int, name VARCHAR(20), deptno int) stored as orc; Note: This is not a duplicate of this issue (Hadoop ORC file - How it works - How to fetch metadata) because the answer tells me to use 'Hive' & I am already using HiveContext as follows: <code>val sqlContext =new org.apache.spark.sql.hive.HiveContext(sc) By the way, I am using my own hive-site.xml, which contains following: <code><configuration> <property> <name>hive.metastore.uris</name> <value>thrift://sandbox.hortonworks.com:9083</value> </property> </configuration> ... View more