Hello all,   Having an issue with sqooping from a Teradata database when using the Teradata method "--fast-export", example sqoop query is below   ``` import -Dhadoop.security.credential.provider.path=jceks:/PATH/TO/password/password.jcecks -Dteradata.db.job.data.dictionary.usexviews=false --connect jdbc:teradata://DATABASE --password-alias password.alias --username USER --connection-manager org.apache.sqoop.teradata.TeradataConnManager --fields-terminated-by '\t' --lines-terminated-by '\n' --null-non-string '' --null-string '' --num-mappers 8 --split-by column3 --target-dir /THE/TARGET/DIR --query SELECT column1,column2,column3 WHERE column3 > '2020-01-01 00:00:00' and column3 <= '2020-01-12 10:41:20' AND $CONDITIONS -- --method internal.fastexport ```   The error I am getting is **Caused by: com.teradata.connector.common.exception.ConnectorException: java.sql.SQLException: [Teradata Database] [TeraJDBC ] [Error 3524] [SQLState 42000] The user does not have CREATE VIEW access to database DATABASE.**   I suspect fast export will implement a staging table/view to be temporarily created, and the job under the hood will be ingesting from the temp table. Is this a sqoop mechanism and is it possible to turn it off?  Alternatively is there a better way to do the same import. I should note that sensitive information(server details) has been removed from the question and that the sqoop query runs fine when I do not use faster export   Thanks   Dan ... View more