Member since
09-16-2021
305
Posts
43
Kudos Received
22
Solutions
My Accepted Solutions
Title | Views | Posted |
---|---|---|
223 | 10-25-2024 05:02 AM | |
1246 | 09-10-2024 07:50 AM | |
544 | 09-04-2024 05:35 AM | |
1408 | 08-28-2024 12:40 AM | |
1006 | 02-09-2024 04:31 AM |
05-28-2024
09:10 PM
Data Loss: When you perform an INSERT OVERWRITE operation in Hive, it completely replaces the data in the target table or partition. if the data is not correctly inserted, it can result in data loss. Column Qualifiers: HBase stores data in a key-value format with rows, column families, and column qualifiers. Issues with specific column qualifiers could be due to schema mismatches or data type incompatibilities. Upserting Data: Upserting (update or insert) in HBase via Hive can be challenging since Hive primarily supports batch processing and doesn't have native support for upsert operations directly. As HBASE handlers tables are external tables. Best Practices and Troubleshooting Schema Matching: Ensure that the schema of the Hive table and the HBase table matches, especially the data types and column qualifiers. Data Types: Be cautious with data types. HBase stores everything as bytes, so type conversions must be handled properly. Error Handling: Implement proper error handling and logging to identify issues during data insertion.
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05-15-2024
05:18 AM
1 Kudo
Any tips for solution?
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03-27-2024
11:44 PM
2 Kudos
The error message indicates Tableau is having trouble connecting to your "ShowData" data source and there's an issue with the SQL query it's trying to run on your Hive database. Let's break down the error and potential solutions: Error Breakdown: Bad Connection: Tableau can't establish a connection to the Hive database. Error Code: B19090E0: Generic Tableau error for connection issues. Error Code: 10002: Hive specific error related to the SQL query. SQL state: TStatus(statusCode:ERROR_STATUS): Hive is encountering an error during query processing. Invalid column reference 'tableausql.fieldname': The specific error points to an invalid column reference in the query. Potential Solutions: Verify Database Connection: Ensure the Hive server is running and accessible from Tableau. Double-check the connection details in your Tableau data source configuration, including server address, port, username, and password. Review SQL Query: The error message highlights "tableausql.fieldname" as an invalid column reference. Check if this field name actually exists in your Hive table. There might be a typo or a case-sensitivity issue. If "tableausql" is a prefix Tableau adds, ensure it's not causing conflicts with your actual column names. Check for Unsupported Functions: In rare cases, Tableau might try to use functions not supported by Hive.
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03-06-2024
02:16 AM
1 Kudo
Hi @Sidhartha Could you please try the following sample def convertDatatype(datatype: String): DataType = {
val convert = datatype match {
case "string" => StringType
case "short" => ShortType
case "int" => IntegerType
case "bigint" => LongType
case "float" => FloatType
case "double" => DoubleType
case "decimal" => DecimalType(38,30)
case "date" => TimestampType
case "boolean" => BooleanType
case "timestamp" => TimestampType
}
convert
}
val input_data = List(Row(1l, "Ranga", 27, BigDecimal(306.000000000000000000)), Row(2l, "Nishanth", 6, BigDecimal(606.000000000000000000)))
val input_rdd = spark.sparkContext.parallelize(input_data)
val hiveCols="id:bigint,name:string,age:int,salary:decimal"
val schemaList = hiveCols.split(",")
val schemaStructType = new StructType(schemaList.map(col => col.split(":")).map(e => StructField(e(0), convertDatatype(e(1)), true)))
val myDF = spark.createDataFrame(input_rdd, schemaStructType)
myDF.printSchema()
myDF.show()
val myDF2 = myDF.withColumn("new_salary", col("salary").cast("double"))
myDF2.printSchema()
myDF2.show()
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03-06-2024
12:38 AM
It seems like there might be an issue with the way you're using single quotes in the loop. The variable eachline should be expanded, but it won't if it's enclosed in single quotes. Try using double quotes around the variable and see if that resolves the issue. Here's the corrected loop: for eachline in "${testarray[@]}"
do
beeline -f "${eachline}.sql"
done This way, the value of eachline will be correctly expanded when constructing the command. Also, ensure that the SQL files are present in the correct path or provide the full path if needed. If the issue persists, please provide more details on the error message or behavior you're experiencing for further assistance.
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03-06-2024
12:31 AM
Hive typically relies on the schema definition provided during table creation, and it doesn't perform automatic type conversion while loading data. If there's a mismatch between the data type in the CSV file and the expected data type in the Hive table, it may result in null or incorrect values. Use the CAST function to explicitly convert the data types during the INSERT statement. INSERT INTO TABLE target_table
SELECT
CAST(column1 AS INT),
CAST(column2 AS STRING),
...
FROM source_table; Preprocess your CSV data before loading it into Hive. You can use tools like Apache NiFi or custom scripts to clean and validate the data before ingestion. Remember to thoroughly validate and clean your data before loading it into Hive to avoid unexpected issues. Also, the choice of method depends on your specific use case and the level of control you want over the data loading process.
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02-11-2024
10:00 PM
2 Kudos
Please review the fs.defaultFS configuration in the core-site.xml file within the Hive process directory and ensure that it does not contain any leading or trailing spaces.
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02-09-2024
04:31 AM
1 Kudo
The error you're encountering indicates that there's an issue with the syntax of your DDL (Data Definition Language) statement, specifically related to the SHOW VIEWS IN clause. Error while compiling statement: FAILED: ParseException line 1:5 cannot recognize input near 'SHOW' 'VIEWS' 'IN' in ddl statement If you are trying to show the views in a particular database, the correct syntax would be: SHOW VIEWS IN your_database_name; Replace your_database_name with the actual name of the database you want to query. Ensure that there are no typos or extraneous characters in the statement. If you are not using a specific database and want to see all views in the current database, you can use: SHOW VIEWS; Double-check your SQL statement for correctness and make sure it adheres to the syntax rules of the database you are working with.
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02-09-2024
04:05 AM
1 Kudo
Make sure dfprocessed datafrmae doesn't contains any empty rows. In Spark, you can identify and filter out empty rows in a DataFrame using the filter operation. Empty rows typically have null or empty values across all columns. // Identify and filter out empty rows
val nonEmptyRowsDF = df.filter(not(df.columns.map(col(_).isNull).reduce(_ || _))) This code uses the filter operation along with the not function and a condition that checks if any column in a row is null. It then removes rows where all columns are null or empty. If you want to check for emptiness based on specific columns, you can specify those columns in the condition: val columnsToCheck = Array("column1", "column2", "column3")
val nonEmptyRowsDF = df.filter(not(columnsToCheck.map(col(_).isNull).reduce(_ || _))) Adjust the column names based on your DataFrame structure. The resulting nonEmptyRowsDF will contain rows that do not have null or empty values in the specified columns.
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01-12-2024
03:04 AM
@yoiun, Did the response assist in resolving your query? If it did, kindly mark the relevant reply as the solution, as it will aid others in locating the answer more easily in the future.
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