Try to update password using kadmin.local after you log into the KDC server, reference here: http://web.mit.edu/KERBEROS/krb5-1.4/krb5-1.4.1/doc/krb5-admin/Changing-Passwords.html Cheers
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@ChineduLB If you go to CM > Sentry > Configuration > search for "database", you should be able to see those database options, the one you need is "Sentry Server Database Password". Plus, you also need to make sure that the username and password you used here can connect to Sentry database. Cheers Eric
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Hi, I do not think there is any different. Spark lazily executes statements, so you second 2 jobs version will behave the same way as the first single job, in my opinion. Cheers Eric
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This confirmes the package is installed correctly, and the JDK is installed to /usr/lib/jvm/java-8-oracle-cloudera/ You may want to use this as JAVA_HOME when configuring CM and the cluster to use this JDK
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We do not want to keep the old partitions. We just want to re-partition the data using the timestamps value. The data only exists currently as partitioned by the string value
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Are you looking for a sequentially growing ID or just a universally unique ID? For the former, you can use Curator over ZooKeeper with this recipe: https://curator.apache.org/curator-recipes/distributed-atomic-long.html For the latter, a UUID generator may suffice. For a more 'distributed' solution, checkout Twitter's Snowflake: https://github.com/twitter-archive/snowflake/tree/snowflake-2010
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Hi, I would suggest to use INT rather than STRING. Firstly, searching based INT type is faster, and secondly, like you said, you can do numeric comparison, which will be different from the STRING type comparison.
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