Created 06-29-2022 02:19 AM
I have a table with an ID, key and 2 columns with each contains pipe separated values. How can i parse column into multiple rows with the respective values?
Table that I have:
ID | key | itemno | value |
1 | A | 1|2|3 | 10|20|30 |
1 | B | 1|2|3 | 40|50|60 |
1 | C | 1|2|3 | 70|80|90 |
Expected output:
ID | key | itemno | value |
1 | A | 1 | 10 |
1 | A | 2 | 20 |
1 | A | 3 | 30 |
1 | B | 1 | 40 |
1 | B | 2 | 50 |
1 | B | 3 | 60 |
1 | C | 1 | 70 |
1 | C | 2 | 80 |
1 | C | 3 | 90 |
Really appreciate the help!
Thanks
Created on 07-25-2022 12:18 AM - edited 07-25-2022 12:21 AM
I am able to achieve it with posexplode, please find my solution below.
create table comm_article(id int, key string, itemno string, value string);
insert into comm_article values(1, 'A', '1|2|3', '10|20|30'), (1, 'B', '1|2|3', '40|50|60'), (1, 'C', '1|2|3', '70|80|90');
select * from comm_article;
+------------------+-------------------+----------------------+---------------------+
| comm_article.id | comm_article.key | comm_article.itemno | comm_article.value |
+------------------+-------------------+----------------------+---------------------+
| 1 | A | 1|2|3 | 10|20|30 |
| 1 | B | 1|2|3 | 40|50|60 |
| 1 | C | 1|2|3 | 70|80|90 |
+------------------+-------------------+----------------------+---------------------+
with t as (select id, key, split(itemno, '[|]') as itemno_arr, split(value, '[|]') as value_arr from comm_article)
select id, key, itemno, value from t
lateral view posexplode(itemno_arr) myTable1 AS myCol1, itemno
lateral view posexplode(value_arr) myTable2 AS myCol2, value
where myCol1 = myCol2;
+-----+------+---------+--------+
| id | key | itemno | value |
+-----+------+---------+--------+
| 1 | A | 1 | 10 |
| 1 | A | 2 | 20 |
| 1 | A | 3 | 30 |
| 1 | B | 1 | 40 |
| 1 | B | 2 | 50 |
| 1 | B | 3 | 60 |
| 1 | C | 1 | 70 |
| 1 | C | 2 | 80 |
| 1 | C | 3 | 90 |
+-----+------+---------+--------+
If this helps to address your ask, please accept the solution.
Created on 07-25-2022 12:18 AM - edited 07-25-2022 12:21 AM
I am able to achieve it with posexplode, please find my solution below.
create table comm_article(id int, key string, itemno string, value string);
insert into comm_article values(1, 'A', '1|2|3', '10|20|30'), (1, 'B', '1|2|3', '40|50|60'), (1, 'C', '1|2|3', '70|80|90');
select * from comm_article;
+------------------+-------------------+----------------------+---------------------+
| comm_article.id | comm_article.key | comm_article.itemno | comm_article.value |
+------------------+-------------------+----------------------+---------------------+
| 1 | A | 1|2|3 | 10|20|30 |
| 1 | B | 1|2|3 | 40|50|60 |
| 1 | C | 1|2|3 | 70|80|90 |
+------------------+-------------------+----------------------+---------------------+
with t as (select id, key, split(itemno, '[|]') as itemno_arr, split(value, '[|]') as value_arr from comm_article)
select id, key, itemno, value from t
lateral view posexplode(itemno_arr) myTable1 AS myCol1, itemno
lateral view posexplode(value_arr) myTable2 AS myCol2, value
where myCol1 = myCol2;
+-----+------+---------+--------+
| id | key | itemno | value |
+-----+------+---------+--------+
| 1 | A | 1 | 10 |
| 1 | A | 2 | 20 |
| 1 | A | 3 | 30 |
| 1 | B | 1 | 40 |
| 1 | B | 2 | 50 |
| 1 | B | 3 | 60 |
| 1 | C | 1 | 70 |
| 1 | C | 2 | 80 |
| 1 | C | 3 | 90 |
+-----+------+---------+--------+
If this helps to address your ask, please accept the solution.
Created 08-01-2022 10:41 PM
@Hafiz Has the reply helped resolve your issue? If so, please mark the appropriate reply as the solution, as it will make it easier for others to find the answer in the future.
Regards,
Vidya Sargur,